Z^2+1=1+3z

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Solution for Z^2+1=1+3z equation: 



^2+1=1+3Z

We move all terms to the left:

^2+1-(1+3Z)=0

We add all the numbers together, and all the variables

-(3Z+1)+1+^2=0

We add all the numbers together, and all the variables

-(3Z+1)=0

We get rid of parentheses

-3Z-1=0

We move all terms containing Z to the left, all other terms to the right

-3Z=1

Z=1/-3

Z=-1/3

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